b^2+12.6b=4

Solution for b^2+12.6b=4 equation:

b^2+12.6b=4

We move all terms to the left:

b^2+12.6b-(4)=0

a = 1; b = 12.6; c = -4;
Δ = b2-4ac
Δ = 12.62-4·1·(-4)
Δ = 174.76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12.6)-\sqrt{174.76}}{2*1}=\frac{-12.6-\sqrt{174.76}}{2}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12.6)+\sqrt{174.76}}{2*1}=\frac{-12.6+\sqrt{174.76}}{2}
$